Birthday List

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Birthday List

Poll ended at Mon Dec 01, 2014 9:14 pm

1. Yes
13
50%
2. No
13
50%
 
Total votes: 26

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philco
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Re: Birthday List

Post by philco »

Jerry I do believe that's what they call "double trouble". Please correct me if I'm wrong. 8)
Phil
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jerryd6818
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Re: Birthday List

Post by jerryd6818 »

Phil, to figure this one you have to use a logarithmic equation so it's actually more than "double trouble". :mrgreen: ::dang:: ::facepalm::
Forged on the anvil of discipline.
The Few. The Proud.
Jerry D.

This country has become more about sub-groups than about it's unity as a nation.

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wazu013
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Re: Birthday List

Post by wazu013 »

jerryd6818 wrote:Phil, to figure this one you have to use a logarithmic equation so it's actually more than "double trouble". :mrgreen: ::dang:: ::facepalm::
Here you go.
Solve 2logb(x) = logb(4) + logb(x – 1)
All of these logs have the same base, but I can't solve yet, because I don't yet have "log equals log". So first I'll have to apply log rules:

2logb(x) = logb(4) + logb(x – 1)

logb(x2) = logb((4)(x – 1))
logb(x2) = logb(4x – 4)

Then:

x2 = 4x – 4
x2 – 4x + 4 = 0
(x – 2)(x – 2) = 0

The solution is x = 2.

::woot::
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jerryd6818
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Re: Birthday List

Post by jerryd6818 »

Smarty pants. I wouldn't know a mathematical log if it bit me in the butt. ::sotb::
Forged on the anvil of discipline.
The Few. The Proud.
Jerry D.

This country has become more about sub-groups than about it's unity as a nation.

"The #72 pattern has got to be pretty close to the perfect knife."
--T.J. Murphy 2012
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carrmillus
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Re: Birthday List

Post by carrmillus »

..................that makes 2 of us, jerry!!!............... ::tu:: ..........................
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